document.write( "Question 310488: (5-x)^1/2 = x + 1 ... solve
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document.write( "(3x + 2)^1/2 - (2x + 7 ) 1/2 = 0 ... solve\r
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document.write( "thank you!!!! \n" );
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Algebra.Com's Answer #221991 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (5-x)^1/2 = x + 1 \n" ); document.write( "Square both sides to get: \n" ); document.write( "5-x = x^2+2x+1 \n" ); document.write( "x^2 + 3x - 4 = 0 \n" ); document.write( "Factor: \n" ); document.write( "(x+4)(x-1) = 0 \n" ); document.write( "x = -4 or x = 1 \n" ); document.write( "--- \n" ); document.write( "Note: x cannot = -4 \n" ); document.write( "Only solution: x = 1 \n" ); document.write( "==========================\r \n" ); document.write( "\n" ); document.write( "(3x + 2)^1/2 - (2x + 7 )^ 1/2 = 0 \n" ); document.write( "--- \n" ); document.write( "(3x+2)^(1/2) = (2x+7)^(1/2) \n" ); document.write( "--- \n" ); document.write( "Square both sides: \n" ); document.write( "3x+2 = 2x+7 \n" ); document.write( "x = 5 \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========================== \n" ); document.write( " |