document.write( "Question 310135: 5(3a-1)²+3=-16(3a-1) \n" ); document.write( "
Algebra.Com's Answer #221983 by scott8148(6628)\"\" \"About 
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let x = (3a-1)\r
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\n" ); document.write( "\n" ); document.write( "5x^2 + 16x + 3 = 0\r
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\n" ); document.write( "\n" ); document.write( "factoring ___ (5x + 1)(x + 3) = 0\r
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\n" ); document.write( "\n" ); document.write( "x = -1/5 ___ 3a - 1 = -1/5 ___ a = 4/15\r
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\n" ); document.write( "\n" ); document.write( "x = -3 ___ 3a - 1 = -3 ___ a = -2/3
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