document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310469>Question 310469</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two pumps operating together can fill a cistern in 4 hours. If one of the pumps working alone can fill the cistern in 6 hours, how long would it take the other pump working alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221967 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221967\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let filling the cistern be = 1 job.\r<BR>\n" );
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document.write( "Both pumps can do the job in 4 hours.<BR>\n" );
document.write( "So they can do 1/4 of the job in 1 hour.<BR>\n" );
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document.write( "one pump does the job in 6 hours .<BR>\n" );
document.write( "So it does 1/6th. of the job in 1 hour.<BR>\n" );
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document.write( "Job done by both - job done by one of them = job done by the other in 1 hour.<BR>\n" );
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document.write( "1/4 - 1/6 <BR>\n" );
document.write( "=3-2 / 12 <BR>\n" );
document.write( "=1/12.<BR>\n" );
document.write( "The other pump does 1/12th job in 1 hour.<BR>\n" );
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document.write( "So it takes 12 hours to do the complete job of filing the cistern alone. </SPAN>\n" );
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