document.write( "Question 310373: the perimeter of a rectangle is 100ft and the area is 400ft(squared).find the dimensions of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "could u write out the full answer step by step
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Algebra.Com's Answer #221941 by ankor@dixie-net.com(22740)\"\" \"About 
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Write an equation for each statement:
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\n" ); document.write( "\"the perimeter of a rectangle is 100ft\"
\n" ); document.write( "2L + 2W = 100
\n" ); document.write( "Simplify, divide thru by 2, results
\n" ); document.write( "L + W = 50
\n" ); document.write( "To use for substitution later, write it:
\n" ); document.write( "L = (50-W)
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\n" ); document.write( "\"the area is 400ft(squared)\"
\n" ); document.write( "L * W = 400
\n" ); document.write( "From the perimeter; replace L with (50-W) in the above equation
\n" ); document.write( "(50-W) * W = 400
\n" ); document.write( "50W - W^2 = 400
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "-W^2 + 50W - 400 = 0
\n" ); document.write( "Easier to factor if we change the signs, multiply by -1, results:
\n" ); document.write( "W^2 - 50W + 400 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(W-40)(W-10) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "W = 40
\n" ); document.write( "and
\n" ); document.write( "W = 10
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\n" ); document.write( ".find the dimensions of the rectangle.
\n" ); document.write( "If W = 40, remember L = (50-W), then
\n" ); document.write( "L = 50 - 40
\n" ); document.write( "L = 10
\n" ); document.write( ":
\n" ); document.write( "If W = 10, then
\n" ); document.write( "L = 50 - 10
\n" ); document.write( "L = 40
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\n" ); document.write( "Generally the length is the longer dimension so 40 by 10 would be the answer
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\n" ); document.write( "You can check this solution by finding the perimeter with these values
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\n" ); document.write( "Was this step-by-step enough to give you an understanding of this??
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