document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=310222>Question 310222</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the number of possible 5-card hands taken from a standard 52-card deck that contain 2 aces and 3 cards that are not aces  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221925 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221925\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the number of possible 5-card hands taken from a standard 52-card deck that contain 2 aces and 3 cards that are not aces <BR>\n" );
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document.write( "# of ways to get 2 aces = 4C2 = 6<BR>\n" );
document.write( "# of ways to get 3 other cards = 48C3<BR>\n" );
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document.write( "# of possible 5-card hands = 52C5  <BR>\n" );
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document.write( "P(2 aces and 3 other cards) = (6*48C3)/52C5 = 0.0399<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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