document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4591>Question 4591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the inside circumference of a circle is 72\" what would the outside circumferece br 6\" out from inter circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2219 by </B><A HREF=/tutors/aboutme.mpl?userid=xcentaur><B>xcentaur(357)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=xcentaur><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c=2*pi*r=72\"<BR>\n" );
document.write( "r=72/2*pi<BR>\n" );
document.write( "R=r+6=(72/2*pi)+6<BR>\n" );
document.write( "C=2*pi*R<BR>\n" );
document.write( "=2*pi<BR>\n" );
document.write( "=2*pi<BR>\n" );
document.write( "=72+12*pi<BR>\n" );
document.write( "=72+(12*22/7)<BR>\n" );
document.write( "=72+(264/7)<BR>\n" );
document.write( "=(504+264)/7<BR>\n" );
document.write( "=768/7<BR>\n" );
document.write( "=109.714\" </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );