document.write( "Question 310072: The equation is: y = 1x2+4x+3\r
\n" ); document.write( "\n" ); document.write( "The parabola graph puts it as: x= -1, -3.\r
\n" ); document.write( "\n" ); document.write( "The equation didn't have negative numbers in it in the first place. So why does the graph make them negatives?
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Algebra.Com's Answer #221770 by Alan3354(69443)\"\" \"About 
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y = x2+4x+3
\n" ); document.write( "The parabola graph puts it as: x= -1, -3.
\n" ); document.write( "The equation didn't have negative numbers in it in the first place. So why does the graph make them negatives?
\n" ); document.write( "---------------
\n" ); document.write( "\"y+=+x%5E2%2B4x%2B3+\"
\n" ); document.write( "Find where y = 0:
\n" ); document.write( "\"x%5E2%2B4x%2B3+=+0\"
\n" ); document.write( "(x+3)*(x+1) = 0
\n" ); document.write( "For the product to be 0, either x+3 = 0 or x+1 = 0
\n" ); document.write( "x+3 = 0
\n" ); document.write( "x = -3
\n" ); document.write( "-------
\n" ); document.write( "x+1 = 0
\n" ); document.write( "x = -1
\n" ); document.write( "
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