document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=306669>Question 306669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a chemical laboratory one carboy contains 12 gallons of acids and 18 gallons of water. Another carboy contains 9 gallons of acid and 3 gallons of water. How many gallons must be drawn from each carboy and combined to form a solution that is 7 gallons acid and 7 gallons water?<BR>\n" );
document.write( "Choices:<BR>\n" );
document.write( "a.) 10 gals from first carboy and 4 gals from second carboy<BR>\n" );
document.write( "b.) 9 gals from first carboy and 5 gals from second carboy<BR>\n" );
document.write( "c.) 8 gals from first carboy and 6 gals from second carboy<BR>\n" );
document.write( "d.) 11 gals from first carboy and 3 gals from second carboy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221737 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221737\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a chemical laboratory <BR>\n" );
document.write( "A. one carboy contains 12 gallons of acids and 18 gallons of water. <BR>\n" );
document.write( "B. Another carboy contains 9 gallons of acid and 3 gallons of water. <BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "How many gallons must be drawn from each carboy and combined to form a solution that is 7 gallons acid and 7 gallons water?<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Acid Equation: 12A + 9B = 7 gallons<BR>\n" );
document.write( "Water Equatio: 18A + 3B = 7 gallons<BR>\n" );
document.write( "--------------------------------------<BR>\n" );
document.write( "Solve by elimination:<BR>\n" );
document.write( "Multiply thru 2nd equation by 3 to get:<BR>\n" );
document.write( "54A + 9B = 21<BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "Subtract the 1st equation from that and solve for A:<BR>\n" );
document.write( "42A = 14<BR>\n" );
document.write( "A = 1/3<BR>\n" );
document.write( "1/3 1st carboy gives 4 gals acid and 6 gals water <BR>\n" );
document.write( "------<BR>\n" );
document.write( "Substitute into 18A + 3B = 7 and solve for B:<BR>\n" );
document.write( "18(1/3) + 3B = 7<BR>\n" );
document.write( "3B = 1<BR>\n" );
document.write( "B = 1/3<BR>\n" );
document.write( "1/3 2nd carboy give 3 gals acid and 1 gal of water<BR>\n" );
document.write( "==============================<BR>\n" );
document.write( "1/3 of 1st carboy = 10 gals<BR>\n" );
document.write( "1/3 of 2nd carboy = 4 gals<BR>\n" );
document.write( "================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=====================================\r<BR>\n" );
document.write( "\n" );
document.write( "Choices:<BR>\n" );
document.write( "a.) 10 gals from first carboy and 4 gals from second carboy<BR>\n" );
document.write( "b.) 9 gals from first carboy and 5 gals from second carboy<BR>\n" );
document.write( "c.) 8 gals from first carboy and 6 gals from second carboy<BR>\n" );
document.write( "d.) 11 gals from first carboy and 3 gals from second carboy<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );