document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=308870>Question 308870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many quarts of a solution with 18% iodine must be added to 40 quarts of water to have a resulting solution with 10% iodine?    Can somebody please explain me in details without any Shortcuts:/ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221732 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221732\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many quarts of a solution with 18% iodine must be added to 40 quarts of water to have a resulting solution with 10% iodine? Can somebody please explain me in details without any Shortcuts:/<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "iodine + iodine = iodine<BR>\n" );
document.write( "0.18x + 0*40 = 0.10(x+40)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "18x + 0 = 10x + 10*40<BR>\n" );
document.write( "8x = 10*40<BR>\n" );
document.write( "x = 10*5<BR>\n" );
document.write( "x = 50 quarts (amt. of 18% solution needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );