document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36191>Question 36191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given the sequence qn=(4n-3)/(2-5n), find q10 and q50.then find lim qn </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22170 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> given the sequence qn=(4n-3)/(2-5n), find q10 and q50.then find lim qn<BR>\n" );
document.write( "PUT N=10 TO GET Q10 AND N=50 TO GET Q50 IN THE ABOVE EQN.<BR>\n" );
document.write( "Q10=(4*10-3)/(2-5*10)=-37/48=-0.771<BR>\n" );
document.write( "Q50=(4*50-3)/(2-5*50)=-197/248=-0.794<BR>\n" );
document.write( "AS REGARDS LIMIT QN , WE SHOULD KNOW LIMIT WHEN?<BR>\n" );
document.write( "SUPPOSE LIMIT AS X GOES TO INFINITY IS <BR>\n" );
document.write( "QN=(4-3/X)/(2/X-5)=-4/5=-0.8...IS THE LIMIT AS X TENDS TO INFINITY.<BR>\n" );
document.write( "YOU CAN SE THIS FROM ABOVE ANSWERS.AT N=10,QN=-0.771...AT N=50,QN=-.794<BR>\n" );
document.write( "LIKE THAT IT APPROACHES -0.8 AS N GROWS FURTHER LARGER AND LARGER\r<BR>\n" );
document.write( "\n" );
document.write( "SUPPOSE LIMIT AS X GOES TO ZERO IS <BR>\n" );
document.write( "QN=(4*0-3)/(2-5*0)=-3/2...IS THE LIMIT AS X TENDS TO ZERO. </SPAN>\n" );
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