document.write( "Question 309886: 2t2 + 4t - 30 \n" ); document.write( "
Algebra.Com's Answer #221698 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming that you want to factor this.\r
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\n" ); document.write( "\n" ); document.write( "\"2t%5E2%2B4t-30\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28t%5E2%2B2t-15%29\" Factor out the GCF \"2\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's try to factor the inner expression \"t%5E2%2B2t-15\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"t%5E2%2B2t-15\", we can see that the first coefficient is \"1\", the second coefficient is \"2\", and the last term is \"-15\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"-15\" to get \"%281%29%28-15%29=-15\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-15\" (the previous product) and add to the second coefficient \"2\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-15\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-15\":\r
\n" ); document.write( "\n" ); document.write( "1,3,5,15\r
\n" ); document.write( "\n" ); document.write( "-1,-3,-5,-15\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-15\".\r
\n" ); document.write( "\n" ); document.write( "1*(-15) = -15
\n" ); document.write( "3*(-5) = -15
\n" ); document.write( "(-1)*(15) = -15
\n" ); document.write( "(-3)*(5) = -15\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"2\":\r
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First NumberSecond NumberSum
1-151+(-15)=-14
3-53+(-5)=-2
-115-1+15=14
-35-3+5=2
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-3\" and \"5\" add to \"2\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-3\" and \"5\" both multiply to \"-15\" and add to \"2\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"2t\" with \"-3t%2B5t\". Remember, \"-3\" and \"5\" add to \"2\". So this shows us that \"-3t%2B5t=2t\".\r
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\n" ); document.write( "\n" ); document.write( "\"t%5E2%2Bhighlight%28-3t%2B5t%29-15\" Replace the second term \"2t\" with \"-3t%2B5t\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28t%5E2-3t%29%2B%285t-15%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"t%28t-3%29%2B%285t-15%29\" Factor out the GCF \"t\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"t%28t-3%29%2B5%28t-3%29\" Factor out \"5\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28t%2B5%29%28t-3%29\" Combine like terms. Or factor out the common term \"t-3\"\r
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\n" ); document.write( "\n" ); document.write( "So \"2%28t%5E2%2B2t-15%29\" then factors further to \"2%28t%2B5%29%28t-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"2t%5E2%2B4t-30\" completely factors to \"2%28t%2B5%29%28t-3%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"2t%5E2%2B4t-30=2%28t%2B5%29%28t-3%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"2%28t%2B5%29%28t-3%29\" to get \"2t%5E2%2B4t-30\" or by graphing the original expression and the answer (the two graphs should be identical).
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