document.write( "Question 309952: the length of a rectangle is 31 centimeters less than five times its width. the area is 72 square centimeters. find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #221685 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the width be x \n" ); document.write( "length will be 5x-31\r \n" ); document.write( "\n" ); document.write( "Area = L*W\r \n" ); document.write( "\n" ); document.write( "72 = x(5x-31) \n" ); document.write( "72=5x^2-31x \n" ); document.write( "5x^2-31x-72=0 \n" ); document.write( ". \n" ); document.write( "x1,x2 the roots of the equation will be\r \n" ); document.write( "\n" ); document.write( "x1= 31+sqrt(-31^2-4*5*-72) / 2*5\r \n" ); document.write( "\n" ); document.write( "x1= 31 +sqrt(-31^2 +1440) /10 \n" ); document.write( "x1= 8\r \n" ); document.write( "\n" ); document.write( "x2 = -1.8\r \n" ); document.write( "\n" ); document.write( "x2 is negative \n" ); document.write( "So width = 8 cms \n" ); document.write( "Then length will be 9cms \n" ); document.write( " |