document.write( "Question 309903: a picture is 1 inch longer than it is wide. It is put into a frame 1/2 inch wide. If the area of the frame is 8 inches by itself, how big is the picture? \n" ); document.write( "
Algebra.Com's Answer #221668 by stanbon(75887)\"\" \"About 
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a picture is 1 inch longer than it is wide. It is put into a frame 1/2 inch wide. If the area of the frame is 8 in^2 by itself, how big is the picture?
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\n" ); document.write( "Draw the picture of a rectangle inside a rectangle.
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\n" ); document.write( "Picture dimentions:, W and L where L = W+1
\n" ); document.write( "Area of Picture only : WL
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\n" ); document.write( "Picture with frame dimentions: W + 1 and L+1
\n" ); document.write( "Area of picture with frame : (W+1)(L+1)
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\n" ); document.write( "Equations
\n" ); document.write( "Total area - picture area = 8 sq. in.
\n" ); document.write( "(W+1)(L+1) - WL = 8
\n" ); document.write( "L + W + 1 = 8
\n" ); document.write( "L+W = 7
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\n" ); document.write( "Substitute W+1 for \"L
\n" ); document.write( "W+1 + W = 7
\n" ); document.write( "2W = 6
\n" ); document.write( "W = 3 in (width of the picture)
\n" ); document.write( "L = W+1 = 4 in (length of the picture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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