document.write( "Question 309870: Two small planes start from the same point and fly in opposite directions. The first plane is flying
\n" ); document.write( "25 miles per hour slower than the second plane. In 2 hours, the planes are 470 miles apart. Find the rate of each plane \n" ); document.write( "

Algebra.Com's Answer #221666 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Think of 1 plane as stationary and the other as moving away from it
\n" ); document.write( "at the sum of their speeds
\n" ); document.write( "Let $\"s\"$ = the speed of the faster plane
\n" ); document.write( " $\"s+-+25\"$ = the speed of the slower plane
\n" ); document.write( "The sum of their speeds is $\"s+%2B+s+-+25+=+2s+-+25\"$
\n" ); document.write( "In 2 hrs:
\n" ); document.write( " $\"470+=+%282s+-+25%29%2A2\"$
\n" ); document.write( " $\"470+=+4s+-+50\"$
\n" ); document.write( " $\"4s+=+520\"$
\n" ); document.write( " $\"s+=+130\"$
\n" ); document.write( " $\"s+-+25+=+105\"$
\n" ); document.write( "The 1st planes flies at 105 mi/hr
\n" ); document.write( "The 2nd plane flies at 130 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "1st plane:
\n" ); document.write( " $\"d%5B1%5D+=+105%2A2\"$
\n" ); document.write( " $\"d%5B1%5D+=+210\"$ mi
\n" ); document.write( "2nd plane:
\n" ); document.write( " $\"d%5B2%5D+=+130%2A2\"$
\n" ); document.write( " $\"d%5B2%5D+=+260\"$
\n" ); document.write( " $\"d%5B1%5D+%2B+d%5B2%5D+=+210+%2B+260\"$
\n" ); document.write( " $\"d%5B1%5D+%2B+d%5B2%5D+=+470\"$
\n" ); document.write( "OK \n" ); document.write( "

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