document.write( "Question 309887: a passenger train and a freight train start at the same time from station that are 405 miles apart and travel toward each other. the rate of the passenger train is twice the rate of the freight train. in 3 hrs, the trains will pass each other, find the rate of each.\r
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Algebra.Com's Answer #221659 by ankor@dixie-net.com(22740)\"\" \"About 
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a passenger train and a freight train start at the same time from station that
\n" ); document.write( "are 405 miles apart and travel toward each other.
\n" ); document.write( " the rate of the passenger train is twice the rate of the freight train.
\n" ); document.write( "in 3 hrs, the trains will pass each other, find the rate of each.
\n" ); document.write( "formulate chart, equation, and solve
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\n" ); document.write( "Let r = rate of the freight train
\n" ); document.write( "then
\n" ); document.write( "2r = rate of the pass train
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\n" ); document.write( "When the trains meet the total dist of the two trains = 405 mi
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\n" ); document.write( "Freight's dist + pass dist = 405 mi
\n" ); document.write( "3r + 3(2r) = 405
\n" ); document.write( "3r + 6r = 405
\n" ); document.write( "9r = 405
\n" ); document.write( "r = \"405%2F9\"
\n" ); document.write( "r = 45 mph is the freight
\n" ); document.write( "then
\n" ); document.write( "2(45) = 90 mph is pass
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\n" ); document.write( "Check solution
\n" ); document.write( "3(45) = 135
\n" ); document.write( "3(90) = 270
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\n" ); document.write( "total: 405
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