document.write( "Question 309779: suppose that you invest $6000 for your money at an annual intrest rate of of 4% and invest the rest of your money in another accont earning annual intrest rate of 11%. if the two investment earn a total of $1065 for the year , find the total amaount of money that you have invested. \r
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document.write( "Please help me solve \n" );
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Algebra.Com's Answer #221656 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 6,000*.04+.11x=1,065 \n" ); document.write( "240+.11x=1,065 \n" ); document.write( ".11x=1,065-240 \n" ); document.write( ".11x=825 \n" ); document.write( "x=825/.11 \n" ); document.write( "x=7,500 ans. for the amount invested @ 11%. \n" ); document.write( "6,000+7,500=$13,500 is the total amount invested. \n" ); document.write( "Proof: \n" ); document.write( "6,000*.04+7,500*.11=1,065 \n" ); document.write( "240+825=1,065 \n" ); document.write( "1,065=1,065 \n" ); document.write( " |