document.write( "Question 309883: 5 times the first of three consecutive even integers is 4 less than twice the sum if the second and third, find the integers\r
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document.write( "a^5 -4 this is as far as I got \n" );
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Algebra.Com's Answer #221644 by mananth(16949) You can put this solution on YOUR website! let the first integer be x \n" ); document.write( "the second will be x+2 \n" ); document.write( "The third will be x+4 \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "5 times the first integer = 5x. \n" ); document.write( "sum of second and third = x+2 + x+4 \n" ); document.write( "= 2x+6 \n" ); document.write( "Twice the sum of second and third \n" ); document.write( "2(2x+6) \n" ); document.write( "4 less than 2(2x+6) \n" ); document.write( "= 2(2x+6)-4 \n" ); document.write( ". \n" ); document.write( "5x=2(2x+6)-4 \n" ); document.write( "5x=4x+12-4 \n" ); document.write( "x= 8 \n" ); document.write( ". \n" ); document.write( "The numbers are 8 , 10, 12 \n" ); document.write( " |