document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309869>Question 309869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive even integers such that the product of the second and third integers is twenty more than ten times the first integer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221616 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221616\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the 3 even integers be: x, x+2 & x+4<BR>\n" );
document.write( "(x+2)(x+4)=10x+20<BR>\n" );
document.write( "x^2+6x+8-10x-20=0<BR>\n" );
document.write( "x^2-4x-12=0<BR>\n" );
document.write( "(x-6)(x+2)=0<BR>\n" );
document.write( "x-6=0<BR>\n" );
document.write( "x=6 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "(6+2)(6+4)=10*6+20<BR>\n" );
document.write( "8*10=60+20<BR>\n" );
document.write( "80=80<BR>\n" );
document.write( "x+2=0<BR>\n" );
document.write( "x=-2 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "(-2+2)(-2+4)=10*-2+20<BR>\n" );
document.write( "0*2=-20+20<BR>\n" );
document.write( "0=0<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );