document.write( "Question 309863: Please help me I am stuck here trying to figure out some algebra the question is a rectangle has a length of 4x and a width of 4x-2. Its perimeter is 12 inchs. find the length and width \n" ); document.write( "
Algebra.Com's Answer #221615 by nerdybill(7384)\"\" \"About 
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a rectangle has a length of 4x and a width of 4x-2. Its perimeter is 12 inchs. find the length and width
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\n" ); document.write( "Since perimeter of any rectangle:
\n" ); document.write( "length + length + width + width = perimeter
\n" ); document.write( "2length + 2width = perimeter
\n" ); document.write( "2(length + width) = perimeter
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\n" ); document.write( "Substitute what was given:
\n" ); document.write( "length = 4x
\n" ); document.write( "width = 2x-2
\n" ); document.write( "perimeter = 12
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\n" ); document.write( "2(4x + 2x-2) = 12
\n" ); document.write( "2(6x-2) = 12
\n" ); document.write( "6x-2 = 6
\n" ); document.write( "6x = 8
\n" ); document.write( "x = 8/6
\n" ); document.write( "x = 4/3
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\n" ); document.write( "length = 4x = 4(4/3) = 16/3 inches
\n" ); document.write( "width = 2x-2 = 2(4/3)-2 = 8/3 -2 = 8/3 - 6/3 = 2/3 inches
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