document.write( "Question 309826: The speed of train A is 16mph slower tan the speed of train B. Train A travels 200 Miles in the same time it takes train b to travel 280 miles. find the speed of each train. \n" ); document.write( "

Algebra.Com's Answer #221603 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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The speed of train A is 16 mph slower than the speed of train B.
\n" ); document.write( " Train A travels 200 Miles in the same time it takes train b to travel 280 miles. find the speed of each train.
\n" ); document.write( ":
\n" ); document.write( "Let s = Train A speed
\n" ); document.write( "then
\n" ); document.write( "(s+16) = Train B speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Train A time = Train B time
\n" ); document.write( " $\"200%2Fs\"$ = $\"280%2F%28s%2B16%29\"$
\n" ); document.write( "Cross multiply
\n" ); document.write( "280s = 200(s+16)
\n" ); document.write( "280s = 200s + 3200
\n" ); document.write( "280s - 200s = 3200
\n" ); document.write( "80s = 3200
\n" ); document.write( "s = $\"3200%2F80\"$
\n" ); document.write( "s = 40 mph for train A
\n" ); document.write( "and
\n" ); document.write( "40 + 16 = 56 mph train B
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the times
\n" ); document.write( "280/56 = 5 hrs
\n" ); document.write( "200/40 = 5 hrs
\n" ); document.write( " \n" ); document.write( "

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