document.write( "Question 309829: Hi,\r
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document.write( "I need help with the following three fraction calculations.\r
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document.write( "1. 12 1/2 + 1/ 1/3\r
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document.write( "The confusing part here for me is, the 1/2 under the 1, how do I make the denominators the same?\r
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document.write( "2. 2/ 1/2 + 1/1/5\r
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document.write( "3. 3/7 x 2 x square root 49 divided 1/9 ?
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document.write( "(sorry I dont know how to make the root or divided sign)\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #221600 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1. 12 1/2 + 1/ 1/3 \n" ); document.write( "------------- \n" ); document.write( "= (2*12+1)/2 + 1*(3/1) \n" ); document.write( "--- \n" ); document.write( "= (25/2) + 3 \n" ); document.write( "--- \n" ); document.write( "= (25/2) + (6/2) \n" ); document.write( "= 31/2 \n" ); document.write( "---------------------------- \n" ); document.write( " \n" ); document.write( "The confusing part here for me is, the 1/2 under the 1, how do I make the denominators the same? \n" ); document.write( "2. 2/ 1/2 + 1/1/5 \n" ); document.write( "Invert the denominators and multiply: \n" ); document.write( "= (2*2) + (1*5) \n" ); document.write( "= 9 \n" ); document.write( "============================== \n" ); document.write( " \n" ); document.write( "3. 3/7 x 2 x square root 49 divided 1/9 ? \n" ); document.write( "--- \n" ); document.write( "(3/7)*2*sqrt(49)/(1/9) \n" ); document.write( "--------------------------- \n" ); document.write( "= (6/7)*(7*9) \n" ); document.write( "= (6/9) \n" ); document.write( "= 2/3 \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |