document.write( "Question 309829: Hi,\r
\n" ); document.write( "\n" ); document.write( "I need help with the following three fraction calculations.\r
\n" ); document.write( "\n" ); document.write( "1. 12 1/2 + 1/ 1/3\r
\n" ); document.write( "\n" ); document.write( "The confusing part here for me is, the 1/2 under the 1, how do I make the denominators the same?\r
\n" ); document.write( "\n" ); document.write( "2. 2/ 1/2 + 1/1/5\r
\n" ); document.write( "\n" ); document.write( "3. 3/7 x 2 x square root 49 divided 1/9 ?
\n" ); document.write( "(sorry I dont know how to make the root or divided sign)\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #221600 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1. 12 1/2 + 1/ 1/3
\n" ); document.write( "-------------
\n" ); document.write( "= (2*12+1)/2 + 1*(3/1)
\n" ); document.write( "---
\n" ); document.write( "= (25/2) + 3
\n" ); document.write( "---
\n" ); document.write( "= (25/2) + (6/2)
\n" ); document.write( "= 31/2
\n" ); document.write( "----------------------------
\n" ); document.write( "
\n" ); document.write( "The confusing part here for me is, the 1/2 under the 1, how do I make the denominators the same?
\n" ); document.write( "2. 2/ 1/2 + 1/1/5
\n" ); document.write( "Invert the denominators and multiply:
\n" ); document.write( "= (2*2) + (1*5)
\n" ); document.write( "= 9
\n" ); document.write( "==============================
\n" ); document.write( "
\n" ); document.write( "3. 3/7 x 2 x square root 49 divided 1/9 ?
\n" ); document.write( "---
\n" ); document.write( "(3/7)*2*sqrt(49)/(1/9)
\n" ); document.write( "---------------------------
\n" ); document.write( "= (6/7)*(7*9)
\n" ); document.write( "= (6/9)
\n" ); document.write( "= 2/3
\n" ); document.write( "===================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );