document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309807>Question 309807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the amount that will be accumulated.<BR>\n" );
document.write( "a principal of $6000 is accumulated with simple interest of 12% for 1 year </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221584 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Amount accumalated = Principal + simple interest\r<BR>\n" );
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document.write( "Simple interest = p*t*r\r<BR>\n" );
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document.write( "p= 6000<BR>\n" );
document.write( "r= 12%<BR>\n" );
document.write( "t=1<BR>\n" );
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document.write( "6000 * 1* 0.12<BR>\n" );
document.write( "= 720<BR>\n" );
document.write( "720 + 6000 = 6720\r<BR>\n" );
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document.write( "Amount accumalated = $6720 at the end of one year.<BR>\n" );
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