document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309782>Question 309782</A>: <I><SPAN STYLE=\"word-break: break-all;\"> annilee's present age is two -thirds of jessie present age. in 8 years of the sum of thier ages wil be 61 years. find the present ages  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221581 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET JESSIE'S AGE BE X<BR>\n" );
document.write( "anillee's age will be 2x/3 years<BR>\n" );
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document.write( "After 8 years\r<BR>\n" );
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document.write( "jessie will be x+8<BR>\n" );
document.write( "anillee will be 2x/3 +8<BR>\n" );
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document.write( "x+8 + 2x/3 + 8 =61\r<BR>\n" );
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document.write( "3x+24 +2x+24= 183\r<BR>\n" );
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document.write( "5x= 183-48\r<BR>\n" );
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document.write( "x= 135/5<BR>\n" );
document.write( "x= 27\r<BR>\n" );
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document.write( "Jessie's age = 27 years\r<BR>\n" );
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document.write( "2/3 * 27 = 18 = anillee's age<BR>\n" );
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