document.write( "Question 309783: one of two supplementary angles is 4degrees more thatn one -third of the other angle . find the measure of each of the angle \n" ); document.write( "

Algebra.Com's Answer #221572 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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one of two supplementary angles is 4 degrees more than one -third of the other angle .
\n" ); document.write( "find the measure of each of the angle
\n" ); document.write( ":
\n" ); document.write( "Let x = one angle
\n" ); document.write( "then
\n" ); document.write( "(180-x) = the other angle
\n" ); document.write( ":
\n" ); document.write( "x = $\"1%2F3\"$ (180 - x) + 4
\n" ); document.write( "Multiply both sides by 3
\n" ); document.write( "3x = 180 - x + 3(4)
\n" ); document.write( "3x = 180 - x + 12
\n" ); document.write( "3x + x = 192
\n" ); document.write( "4x = 192
\n" ); document.write( "x = $\"192%2F4\"$
\n" ); document.write( "x = 48 degrees
\n" ); document.write( "then
\n" ); document.write( "180 - 48 = 132 degrees is the other angle
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if that fits in the statement;
\n" ); document.write( "\"one of two supplementary angles is 4 degrees more than one-third of the other\"
\n" ); document.write( "48 = $\"1%2F3\"$ (132) + 4
\n" ); document.write( "48 = 44 + 4 \n" ); document.write( "

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