document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309694>Question 309694</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Regarding a triangle which has a 90 degree angle...is there a simple formula to take a given diagonal dimension (hypotenuse) and a constant vertical / horizontal dimension relationship (16:9), and determine the vertical / horizontal dimensions from a given diagonal dimension. For example, if I use the basic 16 horizontal dimension, and the basic 9 vertical dimension, the hypotenuse will be 18.357...\r<BR>\n" );
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document.write( "Hence, working in reverse, what would be the formula I could use to plug in a given hypotenuse (20, 22, 23, 24, 25, 50, 100, etc. and using the non variable 16:9 ratio, come up with the vertical and horizontal dimensions?\r<BR>\n" );
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document.write( "I hope I did OK with making my question clear.\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221534 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{x}{\sqrt{337}\right)*16\"> for your long dimension and\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{x}{\sqrt{337}\right)*9\"> for your short dimension\r<BR>\n" );
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document.write( "Where <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE x\"> is your variable screen diagonal </SPAN>\n" );
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