document.write( "Question 36025: Please help! Thanks a million!!!
\n" ); document.write( "Solve the following for X:
\n" ); document.write( "1) log_6(2x)=log_6 (2)+log_6 (3x-4)\r
\n" ); document.write( "\n" ); document.write( "2) 2ln5=ln(4x-13)\r
\n" ); document.write( "\n" ); document.write( "3) log_4(3x+1)=2\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #22153 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1) log_6(2x)=log_6 (2)+log_6 (3x-4)
\n" ); document.write( "Let's just keep in mind that this is all base 6.
\n" ); document.write( "log(2x) = log2 +log(3x-4)
\n" ); document.write( "log2x = log2(3x-4)
\n" ); document.write( "log2x = log(6x-8)
\n" ); document.write( "Take the anti-log of both sides to get:
\n" ); document.write( "2x=6x-8
\n" ); document.write( "4x=8
\n" ); document.write( "x=2
\n" ); document.write( "
\n" ); document.write( "2) 2ln5=ln(4x-13)
\n" ); document.write( "ln25=ln(4x-13
\n" ); document.write( "25 = 4x-13
\n" ); document.write( "4x=38
\n" ); document.write( "x=19/2
\n" ); document.write( "
\n" ); document.write( "3) log_4(3x+1)=2
\n" ); document.write( " 4^2=3x+1
\n" ); document.write( "16=3x+1
\n" ); document.write( "x=5\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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