document.write( "Question 309681: The width is 2 ft less than the length. The area is 8ft^2. What is the length and width? \n" ); document.write( "
Algebra.Com's Answer #221529 by alicealc(293)![]() ![]() ![]() You can put this solution on YOUR website! assuming that it's a rectangle: \n" ); document.write( "width = w \n" ); document.write( "length = l \n" ); document.write( "w = l - 2 \n" ); document.write( "area = l * w \n" ); document.write( "8 = l * (l - 2) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "0 = (l - 4)*(l + 2) \n" ); document.write( "l - 4 = 0 or l + 2 = 0 \n" ); document.write( "l = 4 or l = -2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "because the length can't be in negative number, so: \n" ); document.write( "length= 4 ft \n" ); document.write( "width = l - 2 = 4 - 2 = 2 ft \n" ); document.write( " |