document.write( "Question 309681: The width is 2 ft less than the length. The area is 8ft^2. What is the length and width? \n" ); document.write( "
Algebra.Com's Answer #221529 by alicealc(293)\"\" \"About 
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assuming that it's a rectangle:
\n" ); document.write( "width = w
\n" ); document.write( "length = l
\n" ); document.write( "w = l - 2
\n" ); document.write( "area = l * w
\n" ); document.write( "8 = l * (l - 2)
\n" ); document.write( "\"8+=+l%5E2+-+2l+\"
\n" ); document.write( "\"0+=+l%5E2+-+2l+-+8\"
\n" ); document.write( "0 = (l - 4)*(l + 2)
\n" ); document.write( "l - 4 = 0 or l + 2 = 0
\n" ); document.write( "l = 4 or l = -2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "because the length can't be in negative number, so:
\n" ); document.write( "length= 4 ft
\n" ); document.write( "width = l - 2 = 4 - 2 = 2 ft
\n" ); document.write( "
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