document.write( "Question 309675: Find the area and perimeter of the polygon with vertices A(-3,0), B(3,4) C(5,1),and D(-1,-3) \n" ); document.write( "
Algebra.Com's Answer #221501 by Alan3354(69443)\"\" \"About 
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Find the area and perimeter of the polygon with vertices A(-3,0), B(3,4) C(5,1),and D(-1,-3)
\n" ); document.write( "Area:
\n" ); document.write( "-3 3 5 -1 -3
\n" ); document.write( "0 4 1 -3 0
\n" ); document.write( "--> -12 + 3 -15 + 0 = -24 down slope
\n" ); document.write( "--> 0 + 20 -1 + 9 = 28 up slope
\n" ); document.write( "Diff = 52
\n" ); document.write( "Area = 26 sq units
\n" ); document.write( "Email me if you want to see how to do that at Moral Loophole@aol.com
\n" ); document.write( "---------
\n" ); document.write( "Perimeter:
\n" ); document.write( "Slope of AB = slope of DC
\n" ); document.write( "Slope of BC = slope of AC
\n" ); document.write( "Slope of AB = -1/slope of AD
\n" ); document.write( "--> a rectangle
\n" ); document.write( "Length of AB = sqrt(6^2 + 4^2) = sqrt(52)
\n" ); document.write( "Length of AD = sqrt(2^2 + 3^2) = sqrt(13)
\n" ); document.write( "Perimeter = 2*(AB + AD) = 6sqrt(13)
\n" ); document.write( "-------------
\n" ); document.write( "Area = sqrt(52)*sqrt(13) = sqrt(676)
\n" ); document.write( "Area = 26, same answer as above
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