document.write( "Question 4711: Hi,I hope someone can answer my log question:\r
\n" ); document.write( "\n" ); document.write( "log(x+2)-logx= log (x+5) Solve for x. \r
\n" ); document.write( "\n" ); document.write( "Thanks alot!
\n" ); document.write( "

Algebra.Com's Answer #2215 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
log(x+2)-logx=(x+5) \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use the second law of logarithms \"log+M+-+log+N+=+log+%28M+%2F+N%29+\"to express the left side as a quotient:\r
\n" ); document.write( "\n" ); document.write( "\"log+%28%28x%2B2%29%29+-+log+x+=+log+%28%28x%2B5%29%29+\"
\n" ); document.write( "\"log+%28%28x%2B2%29%2F+%28x%29%29+=+log+%28%28x%2B+5%29%29+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "log M = log N means that M=N.\r
\n" ); document.write( "\n" ); document.write( "Therefore \"+%28x%2B2%29+%2F+x+=+%28x%2B5%29+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Multiply both sides of the equation by x:
\n" ); document.write( "\"x%2B+2+=+x%28x%2B+5%29+\"
\n" ); document.write( "\"x%2B2+=+x%5E2+%2B+5x+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Set equal to zero:
\n" ); document.write( "\"+0+=+x%5E2+%2B+5x+-+x+-+2\"
\n" ); document.write( "\"+0+=+x%5E2++%2B+4x+-+2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Are you sure you copied this right? They \"usually\" factor at this point. Nevertheless,\r
\n" ); document.write( "\n" ); document.write( "Solve by quadratic formula or completing the square. Completing the square is actually easier.\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2++%2B+4x+-+2+=+0\" Add +2 to each side and place a blank space on each side of the equation:\r
\n" ); document.write( "\n" ); document.write( "\"+x%5E2+%2B+4x+%2B+_____+=+2+%2B+_____\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Take half of the x coefficient, and square it. Half of 4 is 2, and 2^2 = 4. Add +4 to each side of the equation on the blank lines above:\r
\n" ); document.write( "\n" ); document.write( "\"+x%5E2+%2B+4x+%2B+4+=+2+%2B+4\"
\n" ); document.write( "\"+%28x%2B+2%29+%5E2+=+6\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Take square root of each side of the equation:
\n" ); document.write( "\"x%2B2+=+0+%2B-+sqrt+%286%29+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Subract 2 from each side:
\n" ); document.write( "\"x=+-2+%2B-+sqrt+%286%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Of course, you must reject the value \"-2+-+sqrt+%286%29\", since it makes the log of a negative. The final answer is \"-2+%2B+sqrt+%286%29+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Are you sure you didn't copy this wrong??\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2 at SCC
\n" ); document.write( "
\n" ); document.write( "
\n" );