document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309693>Question 309693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An 18-year-old runner can complete a 10.0-km course with an average speed of 4.63 m/s. A 50-year-old runner can cover the same distance with an average speed of 3.82 m/s. How much later (in seconds) should the younger runner start in order to finish the course at the same time as the older runner?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221498 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 18 year old runner distance 10 km - speed = 4.63 m/sec.<BR>\n" );
document.write( "50 year old runner distance 10 km  -3.82 m /sec\r<BR>\n" );
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document.write( "The distance is in km and speed in m/sec.\r<BR>\n" );
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document.write( "convert distance to meters\r<BR>\n" );
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document.write( "10km = 10,000 meters.\r<BR>\n" );
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document.write( "time taken by 18 year old = 10000/4.63<BR>\n" );
document.write( "= 2159.82 seconds<BR>\n" );
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document.write( "time taken by 50 year old = 10000/3.82<BR>\n" );
document.write( "= 2617.80 seconds<BR>\n" );
document.write( "457.98 seconds\r<BR>\n" );
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document.write( "He can start 458 seconds later to reach at the same time </SPAN>\n" );
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