document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309598>Question 309598</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the vertical line of a triangle is 24m and the bottom horizontal line is 10m,<BR>\n" );
document.write( "then what would the missing length be? Help please & thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221483 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IF THE VERTICLE LINE IS ONE OF THE SIDES & IT'S A RIGHT TRIANGLE THEN:<BR>\n" );
document.write( "10^2+24^2=C^2<BR>\n" );
document.write( "100+576=C^2<BR>\n" );
document.write( "C^2=676<BR>\n" );
document.write( "C=SQRT676<BR>\n" );
document.write( "C=26 m.<BR>\n" );
document.write( "iF THE VERTICLE ANGLE IS THE MIDDLE HEIGHT OF THE TRIANGLE THEN:<BR>\n" );
document.write( "5^2+24^2=C^2<BR>\n" );
document.write( "25+576=C^2<BR>\n" );
document.write( "C^2=601<BR>\n" );
document.write( "C=SQRT601<BR>\n" );
document.write( "C=24.5m. <BR>\n" );
document.write( "ALL OTHER VERTICLE LINES WILL RESULT IN THE THIRD SIDE BEING BETWEEN <BR>\n" );
document.write( "24.5M. & 26 m. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );