document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309646>Question 309646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Golden Ratio.<BR>\n" );
document.write( "The anceint greeks thought that the most pleasing shape for a rectangle was one for which the ratio fo the length to the width was approximately 8 to 5, the golden ratio. If the length of a rectangular painting is 2 ft longer thann it's width, then for what demensions would the length and width have the golden ratio?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221466 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L/W=8/5<BR>\n" );
document.write( "8/5=(X+2)/X<BR>\n" );
document.write( "8X=5(X+2)<BR>\n" );
document.write( "8X=5X+10<BR>\n" );
document.write( "8X-5X=10<BR>\n" );
document.write( "3X=10<BR>\n" );
document.write( "X=10/3<BR>\n" );
document.write( "X=3.33 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "8/5=(3.33+2)/3.33<BR>\n" );
document.write( "8/5=5.33/3.33<BR>\n" );
document.write( "8*3.33=5*5.33<BR>\n" );
document.write( "26.64~26.65 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );