document.write( "Question 36144: a rectangle has a perimeter of 68 inches. its legnth is 2 inches less than 3 times a width. what are the legth and width of the rectange \n" ); document.write( "
Algebra.Com's Answer #22141 by tran3209(100)![]() ![]() ![]() You can put this solution on YOUR website! Step 1. \n" ); document.write( "-First you must suppose that the width is \"x\". \n" ); document.write( "-The length of the rectangle is 2 inches less than 3 times the width. \n" ); document.write( "So that would make the length (3x-2)\r \n" ); document.write( "\n" ); document.write( "Step 2. \n" ); document.write( "-To find the perimiter of a rectangle: 2W X 2L.\r \n" ); document.write( "\n" ); document.write( "Step 3. \n" ); document.write( "-Form the equation.\r \n" ); document.write( "\n" ); document.write( "2(3x-2) + 2(x) = 68\r \n" ); document.write( "\n" ); document.write( "6x-4 + 2x = 68\r \n" ); document.write( "\n" ); document.write( "8x=64\r \n" ); document.write( "\n" ); document.write( "x=8\r \n" ); document.write( "\n" ); document.write( "The width is 8 inches. \n" ); document.write( "The length is 22 inches.\r \n" ); document.write( "\n" ); document.write( "Check. \n" ); document.write( "2(8)+ 2(22) = 68 inches \n" ); document.write( " |