document.write( "Question 36144: a rectangle has a perimeter of 68 inches. its legnth is 2 inches less than 3 times a width. what are the legth and width of the rectange \n" ); document.write( "
Algebra.Com's Answer #22141 by tran3209(100)\"\" \"About 
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Step 1.
\n" ); document.write( "-First you must suppose that the width is \"x\".
\n" ); document.write( "-The length of the rectangle is 2 inches less than 3 times the width.
\n" ); document.write( "So that would make the length (3x-2)\r
\n" ); document.write( "\n" ); document.write( "Step 2.
\n" ); document.write( "-To find the perimiter of a rectangle: 2W X 2L.\r
\n" ); document.write( "\n" ); document.write( "Step 3.
\n" ); document.write( "-Form the equation.\r
\n" ); document.write( "\n" ); document.write( "2(3x-2) + 2(x) = 68\r
\n" ); document.write( "\n" ); document.write( "6x-4 + 2x = 68\r
\n" ); document.write( "\n" ); document.write( "8x=64\r
\n" ); document.write( "\n" ); document.write( "x=8\r
\n" ); document.write( "\n" ); document.write( "The width is 8 inches.
\n" ); document.write( "The length is 22 inches.\r
\n" ); document.write( "\n" ); document.write( "Check.
\n" ); document.write( "2(8)+ 2(22) = 68 inches
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