document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309572>Question 309572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the product of the numerators when 4/8  and  8/10 are written in lowest<BR>\n" );
document.write( "terms?\r<BR>\n" );
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document.write( "(A) 2 (B) 4 (C) 8 (D) 16 (E) 32 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221408 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the product of the numerators when 4/8  and  8/10 are written in lowest<BR>\n" );
document.write( "terms?\r<BR>\n" );
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document.write( "(A) 2 (B) 4 (C) 8 (D) 16 (E) 32<BR>\n" );
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document.write( "The product of the numerators is 32.<BR>\n" );
document.write( "(4/8)*(8/10) = 32/80<BR>\n" );
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document.write( "After reduction = 2/5<BR>\n" );
document.write( "A 2<BR>\n" );
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document.write( "It's a poorly worded problem. The numerator of the product in lowest terms is 2.<BR>\n" );
document.write( "The \"product of the numerators\" is still 32. </SPAN>\n" );
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