document.write( "Question 309555: $\"system%280.05x+%2B+0.25y+=+44%2C+0.15x+%2B+0.05y+=+48%29+\"$ \n" ); document.write( "

Algebra.Com's Answer #221404 by ichudov(507) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"system%280.05x+%2B+0.25y+=+44%2C+0.15x+%2B+0.05y+=+48%29+\"$
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "

Solved by pluggable solver: SOLVE linear system by SUBSTITUTION

Solve:
\n" ); document.write( "

We'll use substitution. After moving 0.25*y to the right, we get:
\n" ); document.write( " $\"0.05%2Ax+=+44+-+0.25%2Ay\"$ , or $\"x+=+44%2F0.05+-+0.25%2Ay%2F0.05\"$ . Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " $\"0.15%2A%2844%2F0.05+-+0.25%2Ay%2F0.05%29+%2B+0.05%5Cy+=+48\"$ and simplify: So, we know that y=120. Since $\"x+=+44%2F0.05+-+0.25%2Ay%2F0.05\"$ , x=280.
\n" ); document.write( "
\n" ); document.write( " Answer: $\"system%28+x=280%2C+y=120+%29\"$ .
\n" ); document.write( "

\n" ); document.write( " \n" ); document.write( "

\n" );