document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309529>Question 309529</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are complimentary. The larger angle is 1/5 of the smaller angle. Find the measurement of each. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221388 by </B><A HREF=/tutors/aboutme.mpl?userid=alicealc><B>alicealc(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alicealc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> angle 1 = a<BR>\n" );
document.write( "angle 2 = b\r<BR>\n" );
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document.write( "a + b = 90<BR>\n" );
document.write( "b = 1/5 * a<BR>\n" );
document.write( "so,<BR>\n" );
document.write( "a + 1/5 * a = 90<BR>\n" );
document.write( "5/5 * a + 1/5 * a = 90<BR>\n" );
document.write( "6/5 * a = 90<BR>\n" );
document.write( "a = 90 * 5/6<BR>\n" );
document.write( "a = 450/6 = 75<BR>\n" );
document.write( "b = 1/5 * a = 1/5 * 75 = 15\r<BR>\n" );
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document.write( "so, angle 1 = 75 degrees<BR>\n" );
document.write( "angle 2 = 15 degrees<BR>\n" );
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