document.write( "Question 309449: The volume of a cylindrical can is 500 cubed cm. the material used to make the top and bottom costs .o12 cent/squared cm, the material used for the sides costs .01 cent/ squared cm, and the seam joining the top and bottom to the sides costs .015 cent/cm. what size can would cost the least to produce?
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Algebra.Com's Answer #221325 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! The can is a cylinder of radius R and length L. \n" ); document.write( " \n" ); document.write( "The total cost is the cost of the top and bottom plus the cost of the sidewall. The costs are based on total area. \n" ); document.write( "The top and bottom are both circles of radius R. \n" ); document.write( " \n" ); document.write( "The contribution to the total cost is, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Its contribution to the total cost is, \n" ); document.write( " \n" ); document.write( "The final contributor to cost is the seam which is length L. \n" ); document.write( "Its contribution is \n" ); document.write( " \n" ); document.write( "The total cost equation is then \n" ); document.write( " \n" ); document.write( "Using the volume equation you can get L as a function of R. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now substitute into the cost equation, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now you have total cost as the function of one variable. \n" ); document.write( "To find the minimum cost, take the derivative and set it equal to zero. \n" ); document.write( " \n" ); document.write( "I solved this numerically in EXCEL and got \n" ); document.write( "From that, then use the volume equation to find R. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |