document.write( "Question 309466: Im REALLY stuck on this Algebra Equasion, Please Help Me!!!\r
\n" ); document.write( "\n" ); document.write( "I have these 2 formulas\r
\n" ); document.write( "\n" ); document.write( "12-x^2 -2xy = 0
\n" ); document.write( "...12-y^2 - 2xy = 0\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "for some reason x and y are both 2\r
\n" ); document.write( "\n" ); document.write( "how do you get this
\n" ); document.write( "i tried and got\r
\n" ); document.write( "\n" ); document.write( "y= 6/x -0.5x tried to sub into second one but gets messy any way to do this on a calculator by any chance but i want to know how to do it algebraically hmmmmm........ \n" ); document.write( "
Algebra.Com's Answer #221322 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
What would happen if you set them equal to each other since they both equal zero\r
\n" ); document.write( "\n" ); document.write( "12-x^2 -2xy=12-y^2 - 2xy
\n" ); document.write( "add 2xy to both sides
\n" ); document.write( "12-x^2=12-y^2
\n" ); document.write( "subtract 12
\n" ); document.write( "-x^2=-y^2
\n" ); document.write( "multiply by -1
\n" ); document.write( "x^2=y^2
\n" ); document.write( "so we know that x=y
\n" ); document.write( "12-x^2-2xy=0
\n" ); document.write( "12-x^2-2x^2=0
\n" ); document.write( "12-3x^2=0
\n" ); document.write( "12=3x^2
\n" ); document.write( "4=x^2
\n" ); document.write( "x=+-2
\n" ); document.write( "solutions are
\n" ); document.write( "(2,2)
\n" ); document.write( "(-2,-2)
\n" ); document.write( "now check them to make sure they both work.
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