document.write( "Question 309381: I do not have a very large understanding of logarithms, and i can't solve the question:\r
\n" ); document.write( "\n" ); document.write( "log 7 + log x = 2\r
\n" ); document.write( "\n" ); document.write( "(The answer is 100/7)\r
\n" ); document.write( "\n" ); document.write( "I can solve things such as log x - log 6 = log 15 without having to worry about the base 10, but i do not understand when i need to use it to get the right answer.
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Algebra.Com's Answer #221277 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"Log%287%29%2BLog%28x%29+=+2\" First, apply the \"product rule\" for logarithms: \"Log%28M%29%2BLog%28N%29+=+Log%28M%2AN%29\"
\n" ); document.write( "\"Log%287%2Ax%29+=+2\" Now write this in exponential form: \"Log%5Bb%5D%28x%29+=+y\"--->\"b%5Ey+=+x\"
\n" ); document.write( "\"10%5E2+=+7%2Ax\" Divide both sides by 7.
\n" ); document.write( "\"10%5E2%2F7+=+x\" S0...
\n" ); document.write( "\"highlight%28x+=+100%2F7%29\"
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