document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309361>Question 309361</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the inverse of f(x)= 3x-4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221264 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let f(x) = y\r<BR>\n" );
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document.write( "y = 3x - 4\r<BR>\n" );
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document.write( "Switch x and y.\r<BR>\n" );
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document.write( "x = 3y - 4\r<BR>\n" );
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document.write( "Add 4 to both sides.\r<BR>\n" );
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document.write( "x + 4 = 3y\r<BR>\n" );
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document.write( "Divide both sides by 3.\r<BR>\n" );
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document.write( "(x + 4)/3 = y\r<BR>\n" );
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document.write( "Replace y with the inverse notation f^-1 (x).\r<BR>\n" );
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document.write( "(x + 4)/3 = f^-1 (x) </SPAN>\n" );
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