document.write( "Question 309347: Solve using substitution method.\r
\n" ); document.write( "\n" ); document.write( "a - 2b = 3
\n" ); document.write( "3a = 6b + 9
\n" ); document.write( "
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Algebra.Com's Answer #221250 by stanbon(75887)\"\" \"About 
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Solve using substitution method.
\n" ); document.write( "a - 2b = 3
\n" ); document.write( "3a = 6b + 9
\n" ); document.write( "-----------------
\n" ); document.write( "Rearrange:
\n" ); document.write( "a = 2b+3
\n" ); document.write( "----
\n" ); document.write( "Substitute for \"a\" and solve for \"b\":
\n" ); document.write( "2b+3 = 6b+9
\n" ); document.write( "4b = -6
\n" ); document.write( "b = -3/2
\n" ); document.write( "-----
\n" ); document.write( "Since a = 2b+3, a = 2(-3/2)+3 = 0
\n" ); document.write( "====================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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