document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=309271>Question 309271</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 22 m long. The<BR>\n" );
document.write( "length of one leg is 10 m less than the other. Find<BR>\n" );
document.write( "the lengths of the legs.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #221200 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=221200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 22 m long. The<BR>\n" );
document.write( "length of one leg is 10 m less than the other. Find<BR>\n" );
document.write( "the lengths of the legs.<BR>\n" );
document.write( "let one leg be x<BR>\n" );
document.write( "the other leg will be x-10\r<BR>\n" );
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document.write( "x^2 +(x-10)^2=22^2<BR>\n" );
document.write( "x^2+x^2-20x+100=484\r<BR>\n" );
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document.write( "2x^2-20x-384=0<BR>\n" );
document.write( "2(x^2-10x-192)=0<BR>\n" );
document.write( "x^2-10x-192=0<BR>\n" );
document.write( "x1= 10+sqrt(100+768) / 2<BR>\n" );
document.write( "x1=19.731<BR>\n" );
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document.write( "x2= 10-sqrt(100+768) / 2<BR>\n" );
document.write( "x2=-9.731\r<BR>\n" );
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document.write( "Since x1 is positve  x= 19.731\r<BR>\n" );
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document.write( "The other leg = 9.731\r<BR>\n" );
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document.write( "Checking\r<BR>\n" );
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document.write( "(19.731)^2 + (9.731)^2= 484 .00\r<BR>\n" );
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