document.write( "Question 309262: log3 4x + log3 (x-4) = 2 \n" ); document.write( "

Algebra.Com's Answer #221165 by Earlsdon(6294) $\"\"$ $\"About$

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Solve for x:
\n" ); document.write( " $\"Log%5B3%5D%284x%29%2BLog%5B3%5D%28x-4%29+=+2\"$ Apply the \"product rule\" for logarithms.
\n" ); document.write( " $\"Log%5B3%5D%28%284x%29%28x-4%29%29+=+2\"$ Multiply the arguments.
\n" ); document.write( " $\"Log%5B3%5D%284x%5E2-16x%29+=+2\"$ Rewrite in exponential form.
\n" ); document.write( " $\"3%5E2+=+4x%5E2-16x\"$ Write this as a quadratic equation in standard form.
\n" ); document.write( " $\"4x%5E2-16x-9+=+0\"$ Solve by factoring.
\n" ); document.write( " $\"%282x-9%29%282x%2B1%29+=+0\"$ Apply the \"zero product\" rule.
\n" ); document.write( " $\"2x-9+=+0\"$ or $\"2x%2B1+=+0\"$ so...
\n" ); document.write( " $\"2x+=+9\"$ or $\"2x+=+-1\"$ and...
\n" ); document.write( " $\"highlight%28x+=+9%2F2%29\"$ or $\"highlight%28x+=+-1%2F2%29\"$ \n" ); document.write( "

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