document.write( "Question 309231: This actually has to do with radical equations, but can you please explain how you'd solve the equation 1 over t-2 = t over 8.
\n" ); document.write( "I think you can read that better, but its 1/t-2 = t/8, and I'm supposed to solve for t.
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Algebra.Com's Answer #221119 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I think you meant to say rational equations. Radical equations look something like this \"sqrt%28x%29=10\". Also, you can use parenthesis to show that 't-2' is underneath 1 by typing 1/(t-2)\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%28t-2%29+=+t%2F8\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"1%2A8+=+t%28t-2%29\" Cross multiply\r
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\n" ); document.write( "\n" ); document.write( "\"1%2A8+=+t%2At-t%2A2\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"8+=+t%5E2-2t\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"0+=+t%5E2-2t-8\" Subtract 8 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"t%5E2-2t-8\" is in the form of \"At%5E2%2BBt%2BC\" where \"A=1\", \"B=-2\", and \"C=-8\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"t\":\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%281%29%28-8%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=-2\", and \"C=-8\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%281%29%28-8%29+%29%29%2F%282%281%29%29\" Negate \"-2\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%282+%2B-+sqrt%28+4-4%281%29%28-8%29+%29%29%2F%282%281%29%29\" Square \"-2\" to get \"4\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%282+%2B-+sqrt%28+4--32+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-8%29\" to get \"-32\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%282+%2B-+sqrt%28+4%2B32+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%284--32%29\" as \"sqrt%284%2B32%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%282+%2B-+sqrt%28+36+%29%29%2F%282%281%29%29\" Add \"4\" to \"32\" to get \"36\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%282+%2B-+sqrt%28+36+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%282+%2B-+6%29%2F%282%29\" Take the square root of \"36\" to get \"6\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%282+%2B+6%29%2F%282%29\" or \"t+=+%282+-+6%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%288%29%2F%282%29\" or \"t+=++%28-4%29%2F%282%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+4\" or \"t+=+-2\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"t+=+4\" or \"t+=+-2\"
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