document.write( "Question 309180: Please help!!
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document.write( "The answer is 19.. I just don't know how to get it. I keep getting 18 as an answer.\r
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document.write( "A construction company spent 26 hours on two jobs. One job took 5 more the twice the number of hours of the other. How long did the larger job take?\r
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document.write( "Thank you so much for your help!!\r
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document.write( "Rebecca \n" );
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Algebra.Com's Answer #221046 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A construction company spent 26 hours on two jobs. \n" ); document.write( " One job took 5 more the twice the number of hours of the other. \n" ); document.write( " How long did the larger job take? \n" ); document.write( ": \n" ); document.write( "Let x = time for larger job \n" ); document.write( "Let y = time for the other job \n" ); document.write( ": \n" ); document.write( "\"A construction company spent 26 hours on two jobs.\" \n" ); document.write( "x + y = 26 \n" ); document.write( "y = (26-x); this form for substitution \n" ); document.write( ": \n" ); document.write( "\"One job took 5 more the twice the number of hours of the other.\" \n" ); document.write( "x = 2y + 5 \n" ); document.write( ": \n" ); document.write( " How long did the larger job take? \n" ); document.write( "Replace y with (26-x) in the above equation \n" ); document.write( "x = 2(26-x) + 5 \n" ); document.write( "x = 52 - 2x + 5 \n" ); document.write( "x + 2x = 52 + 5 \n" ); document.write( "3x = 57 \n" ); document.write( "x = \n" ); document.write( "x = 19 hrs \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution; y = 26-19 = 7 hrs \n" ); document.write( "\"One job took 5 more the twice the number of hours of the other.\" \n" ); document.write( "19 = 2(7) + 5 \n" ); document.write( " |