document.write( "Question 309160: The square of Mark's age 3 years ago is 6 times the age he will be in 9 years. What is his age now? \n" ); document.write( "
Algebra.Com's Answer #221032 by texttutoring(324)\"\" \"About 
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The square of Mark's age 3 years ago\r
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\n" ); document.write( "\n" ); document.write( "Let x = Mark's age now.\r
\n" ); document.write( "\n" ); document.write( "3 years ago, he was (x-3) years old. The square of his age 3 years ago is (x-3)^2\r
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\n" ); document.write( "\n" ); document.write( "In 9 years (x+9), Mark will be 6 times the square of his (x-3) age.\r
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\n" ); document.write( "\n" ); document.write( "(x-3)^2 = 6(x+9)
\n" ); document.write( "(x^2-6x+9) = 6x+54
\n" ); document.write( "x^2 - 12x -45 = 0\r
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\n" ); document.write( "\n" ); document.write( "Factor this. Think what numbers multiply to -45 but add up to -12? -15 and 3.\r
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\n" ); document.write( "\n" ); document.write( "(x-15)(x+3)=0\r
\n" ); document.write( "\n" ); document.write( "x=15, or x=-3\r
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\n" ); document.write( "\n" ); document.write( "We can eliminate x=-3, because Mark can't have a negative age.\r
\n" ); document.write( "\n" ); document.write( "Mark is 15 years old now.
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