document.write( "Question 309140: the equation 2x-3x^1/2 + 1 = 0 has two solutions. The sum of the solutions is:\r
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document.write( "a 1 b 1/2 c 5/4 d 4 e 3/2 \n" );
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Algebra.Com's Answer #221013 by texttutoring(324)![]() ![]() You can put this solution on YOUR website! Recall that x^1/2 is the same as Sqrt(x).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factor:\r \n" ); document.write( "\n" ); document.write( "2x -3x^(1/2) +1 =0 \n" ); document.write( "(2x^(1/2) - 1)(x^(1/2) - 1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So either:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x^(1/2) - 1 =0 \n" ); document.write( "2x^(1/2)=1 \n" ); document.write( "x=1/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "OR\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^(1/2) - 1 = 0 \n" ); document.write( "x^(1/2) = 1 \n" ); document.write( "x= 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 1+1/4 to get 5/4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of the answers is 5/4. \n" ); document.write( " |