document.write( "Question 309100: Please show work
\n" ); document.write( "Two negative integers have a sum of -10. If the sum of their squares is 68, than what are the two integers?
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Algebra.Com's Answer #221002 by Fombitz(32388)\"\" \"About 
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1.\"A%2BB=-10\"
\n" ); document.write( "2.\"A%5E2%2BB%5E2=68\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"A=-10-B=-%28B%2B10%29\"
\n" ); document.write( "\"A%5E2=%28B%2B10%29%5E2\"
\n" ); document.write( "\"A%5E2=B%5E2%2B20B%2B100\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"A%5E2%2BB%5E2=68\"
\n" ); document.write( "\"B%5E2%2B20B%2B100%2BB%5E2=68\"
\n" ); document.write( "\"2B%5E2%2B20B%2B32=0\"
\n" ); document.write( "\"B%5E2%2B10B%2B16=0\"
\n" ); document.write( "\"%28B%2B2%29%28B%2B8%29=0\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"B%2B2=0\"\r
\n" ); document.write( "\n" ); document.write( "\"B=-2\"
\n" ); document.write( ", then from eq. 1, \"+A=-8+\"
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\n" ); document.write( "\"B%2B8=0\"\r
\n" ); document.write( "\n" ); document.write( "\"B=-8\"
\n" ); document.write( ", then from eq. 1, \"A=-2\"
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\n" ); document.write( ".
\n" ); document.write( "-2 and -8 are your two integers.
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