document.write( "Question 31444: 1) There are 10 people in the room. 6 are male and 4 are female. 5 of them have been arrested at some point in their lives. 4 of these five people are male. If you select 5 people at random what is the probability that at least 3 of them are males who have been arrested and at least one of them is a female who has not been arrested? \n" ); document.write( "
Algebra.Com's Answer #22098 by stanbon(75887)\"\" \"About 
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1) There are 10 people in the room. 6 are male and 4 are female. 5 of them have been arrested at some point in their lives. 4 of these five people are male. If you select 5 people at random what is the probability that at least 3 of them are males who have been arrested and at least one of them is a female who has not been arrested?\r
\n" ); document.write( "\n" ); document.write( "Draw the Venn diagram of your problem.
\n" ); document.write( "Your selection requirements can be met in two
\n" ); document.write( "disjoint ways:
\n" ); document.write( "Case 1: Select 3 arrested males from the four available and
\n" ); document.write( " select 2 females from the 3 that have not been arrested.
\n" ); document.write( "Number of ways to do this is 4C3*3C2 = 4(3)= 12
\n" ); document.write( "Case 2: Select 4 arrested males from the four available and
\n" ); document.write( " select 1 female from the 3 that have not been arrested.
\n" ); document.write( "Number of ways to do this is 4C4*3C1 = 1(3)=3
\n" ); document.write( "Total number of ways to succeed is 12+3=15
\n" ); document.write( "Total number of groups of 5 that could be selected is 10C5
\n" ); document.write( "Probability of meeting your selection criteria = 16/10C5 = 0.0595...
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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