document.write( "Question 36073: solve: log(6x)-log(x+1)=log4 \n" ); document.write( "

Algebra.Com's Answer #22097 by Earlsdon(6294) $\"\"$ $\"About$

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Recall that: $\"log%28M%29-log%28N%29+=+log%28M%2FN%29\"$ and if $\"log%28A%29+=+log%28B%29\"$ then $\"A+=+B\"$ Applying these ideas to your problem:
\n" ); document.write( " $\"log%28%286x%29%29-log%28%28x%2B1%29%29+=+log%28%284%29%29\"$
\n" ); document.write( " $\"log%28%28%286x%29%2F%28x%2B1%29%29%29+=+log%28%284%29%29\"$
\n" ); document.write( " $\"%28%286x%29%2F%28x%2B1%29%29+=+4\"$ Multiply both sides by (x+1)
\n" ); document.write( " $\"6x+=+4%28x%2B1%29\"$ Simplify.
\n" ); document.write( " $\"6x+=+4x%2B4\"$ Subtract 4x from both sides.
\n" ); document.write( " $\"2x+=+4\"$ Finally, divide both sides by 2.
\n" ); document.write( " $\"x+=+2\"$ \n" ); document.write( "

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